Base | Representation |
---|---|
bin | 11011100010010010111010… |
… | …110001000110100010000111 |
3 | 120212210102200011110200010022 |
4 | 123202102322301012202013 |
5 | 111333132024003441012 |
6 | 1105322231323245355 |
7 | 34336322535410012 |
oct | 3342227261064207 |
9 | 525712604420108 |
10 | 121104031312007 |
11 | 35650a27555617 |
12 | 116ba93307985b |
13 | 52760a446a863 |
14 | 21c9675abc379 |
15 | e002d8eb4472 |
hex | 6e24bac46887 |
121104031312007 has 2 divisors, whose sum is σ = 121104031312008. Its totient is φ = 121104031312006.
The previous prime is 121104031311959. The next prime is 121104031312051. The reversal of 121104031312007 is 700213130401121.
It is a strong prime.
It is an emirp because it is prime and its reverse (700213130401121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121104031312007 - 26 = 121104031311943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121104031312097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60552015656003 + 60552015656004.
It is an arithmetic number, because the mean of its divisors is an integer number (60552015656004).
Almost surely, 2121104031312007 is an apocalyptic number.
121104031312007 is a deficient number, since it is larger than the sum of its proper divisors (1).
121104031312007 is an equidigital number, since it uses as much as digits as its factorization.
121104031312007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 121104031312007 its reverse (700213130401121), we get a palindrome (821317161713128).
The spelling of 121104031312007 in words is "one hundred twenty-one trillion, one hundred four billion, thirty-one million, three hundred twelve thousand, seven".
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