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121109993821493 is a prime number
BaseRepresentation
bin11011100010011000011110…
…001010010001010100110101
3120212211000001200222112110222
4123202120132022101110311
5111333231231404241433
61105325055120424125
734336623356041415
oct3342303612212465
9525730050875428
10121109993821493
11356535071aa206
12116bbb17a78045
13527681483b091
1421c9a7d92c645
15e00537693b98
hex6e261e291535

121109993821493 has 2 divisors, whose sum is σ = 121109993821494. Its totient is φ = 121109993821492.

The previous prime is 121109993821441. The next prime is 121109993821501. The reversal of 121109993821493 is 394128399901121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111040529030929 + 10069464790564 = 10537577^2 + 3173242^2 .

It is a cyclic number.

It is not a de Polignac number, because 121109993821493 - 28 = 121109993821237 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121109993821433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60554996910746 + 60554996910747.

It is an arithmetic number, because the mean of its divisors is an integer number (60554996910747).

Almost surely, 2121109993821493 is an apocalyptic number.

It is an amenable number.

121109993821493 is a deficient number, since it is larger than the sum of its proper divisors (1).

121109993821493 is an equidigital number, since it uses as much as digits as its factorization.

121109993821493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7558272, while the sum is 62.

The spelling of 121109993821493 in words is "one hundred twenty-one trillion, one hundred nine billion, nine hundred ninety-three million, eight hundred twenty-one thousand, four hundred ninety-three".