Base | Representation |
---|---|
bin | 1011000000111101000100… |
… | …0111000111011101100111 |
3 | 1120212210122212212220022202 |
4 | 2300033101013013131213 |
5 | 3041411332401024033 |
6 | 41431420513445115 |
7 | 2356664251621253 |
oct | 260172107073547 |
9 | 46783585786282 |
10 | 12111021111143 |
11 | 394a289757919 |
12 | 143724457079b |
13 | 69b0ab608a66 |
14 | 2dc268647263 |
15 | 16007e9b98e8 |
hex | b03d11c7767 |
12111021111143 has 2 divisors, whose sum is σ = 12111021111144. Its totient is φ = 12111021111142.
The previous prime is 12111021111113. The next prime is 12111021111149. The reversal of 12111021111143 is 34111112011121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12111021111143 - 220 = 12111020062567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111021111149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055510555571 + 6055510555572.
It is an arithmetic number, because the mean of its divisors is an integer number (6055510555572).
Almost surely, 212111021111143 is an apocalyptic number.
12111021111143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111021111143 is an equidigital number, since it uses as much as digits as its factorization.
12111021111143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 12111021111143 its reverse (34111112011121), we get a palindrome (46222133122264).
The spelling of 12111021111143 in words is "twelve trillion, one hundred eleven billion, twenty-one million, one hundred eleven thousand, one hundred forty-three".
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