Base | Representation |
---|---|
bin | 1011000000111101000100… |
… | …0111100010010010111101 |
3 | 1120212210122220002111002111 |
4 | 2300033101013202102331 |
5 | 3041411332413033203 |
6 | 41431420520054021 |
7 | 2356664252556556 |
oct | 260172107422275 |
9 | 46783586074074 |
10 | 12111021221053 |
11 | 394a289822457 |
12 | 1437244604311 |
13 | 69b0ab646ab1 |
14 | 2dc26867532d |
15 | 16007e9dc26d |
hex | b03d11e24bd |
12111021221053 has 2 divisors, whose sum is σ = 12111021221054. Its totient is φ = 12111021221052.
The previous prime is 12111021221009. The next prime is 12111021221059. The reversal of 12111021221053 is 35012212011121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11839916682724 + 271104538329 = 3440918^2 + 520677^2 .
It is a cyclic number.
It is not a de Polignac number, because 12111021221053 - 213 = 12111021212861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111021221059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055510610526 + 6055510610527.
It is an arithmetic number, because the mean of its divisors is an integer number (6055510610527).
Almost surely, 212111021221053 is an apocalyptic number.
It is an amenable number.
12111021221053 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111021221053 is an equidigital number, since it uses as much as digits as its factorization.
12111021221053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 12111021221053 its reverse (35012212011121), we get a palindrome (47123233232174).
The spelling of 12111021221053 in words is "twelve trillion, one hundred eleven billion, twenty-one million, two hundred twenty-one thousand, fifty-three".
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