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12111100100153 is a prime number
BaseRepresentation
bin1011000000111101010111…
…0100011011111000111001
31120212210212101111221212122
42300033111310123320321
53041412013111201103
641431432414451025
72356666231204025
oct260172564337071
946783771457778
1012111100100153
11394a31a2a849a
121437266b03a75
1369b0c1aa3c12
142dc274d29385
151600868bdb38
hexb03d5d1be39

12111100100153 has 2 divisors, whose sum is σ = 12111100100154. Its totient is φ = 12111100100152.

The previous prime is 12111100100147. The next prime is 12111100100219. The reversal of 12111100100153 is 35100100111121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10058336134144 + 2052763966009 = 3171488^2 + 1432747^2 .

It is a cyclic number.

It is not a de Polignac number, because 12111100100153 - 212 = 12111100096057 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12111100100053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055550050076 + 6055550050077.

It is an arithmetic number, because the mean of its divisors is an integer number (6055550050077).

Almost surely, 212111100100153 is an apocalyptic number.

It is an amenable number.

12111100100153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111100100153 is an equidigital number, since it uses as much as digits as its factorization.

12111100100153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 17.

Adding to 12111100100153 its reverse (35100100111121), we get a palindrome (47211200211274).

The spelling of 12111100100153 in words is "twelve trillion, one hundred eleven billion, one hundred million, one hundred thousand, one hundred fifty-three".