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12111111012001 is a prime number
BaseRepresentation
bin1011000000111101011001…
…1110000011111010100001
31120212210220011001100010011
42300033112132003322201
53041412023404341001
641431433444404521
72356666423022011
oct260172636037241
946783804040104
1012111111012001
11394a325480751
12143726a6a6741
1369b0c4124831
142dc276569c41
15160087826d51
hexb03d6783ea1

12111111012001 has 2 divisors, whose sum is σ = 12111111012002. Its totient is φ = 12111111012000.

The previous prime is 12111111011999. The next prime is 12111111012061. The reversal of 12111111012001 is 10021011111121.

12111111012001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6899369022225 + 5211741989776 = 2626665^2 + 2282924^2 .

It is a cyclic number.

It is not a de Polignac number, because 12111111012001 - 21 = 12111111011999 is a prime.

Together with 12111111011999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12111111012061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055555506000 + 6055555506001.

It is an arithmetic number, because the mean of its divisors is an integer number (6055555506001).

Almost surely, 212111111012001 is an apocalyptic number.

It is an amenable number.

12111111012001 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111111012001 is an equidigital number, since it uses as much as digits as its factorization.

12111111012001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 12111111012001 its reverse (10021011111121), we get a palindrome (22132122123122).

The spelling of 12111111012001 in words is "twelve trillion, one hundred eleven billion, one hundred eleven million, twelve thousand, one".