Base | Representation |
---|---|
bin | 1011000000111101011110… |
… | …1010101100010101010111 |
3 | 1120212210221112211221100202 |
4 | 2300033113222230111113 |
5 | 3041412044030204003 |
6 | 41431435443131115 |
7 | 2360000055540041 |
oct | 260172752542527 |
9 | 46783845757322 |
10 | 12111131100503 |
11 | 394a335851516 |
12 | 1437275373a9b |
13 | 69b0c8339316 |
14 | 2dc2790b8a91 |
15 | 160089494088 |
hex | b03d7aac557 |
12111131100503 has 2 divisors, whose sum is σ = 12111131100504. Its totient is φ = 12111131100502.
The previous prime is 12111131100487. The next prime is 12111131100583. The reversal of 12111131100503 is 30500113111121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12111131100503 - 24 = 12111131100487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111131100583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055565550251 + 6055565550252.
It is an arithmetic number, because the mean of its divisors is an integer number (6055565550252).
Almost surely, 212111131100503 is an apocalyptic number.
12111131100503 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111131100503 is an equidigital number, since it uses as much as digits as its factorization.
12111131100503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 12111131100503 its reverse (30500113111121), we get a palindrome (42611244211624).
The spelling of 12111131100503 in words is "twelve trillion, one hundred eleven billion, one hundred thirty-one million, one hundred thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •