Base | Representation |
---|---|
bin | 1011000000111101110001… |
… | …1011111100010111111010 |
3 | 1120212211011010102100122100 |
4 | 2300033130123330113322 |
5 | 3041412230021320442 |
6 | 41431451422204230 |
7 | 2360002046644302 |
oct | 260173433742772 |
9 | 46784133370570 |
10 | 12111211120122 |
11 | 394a376a36434 |
12 | 1437298123676 |
13 | 69b10baa55ca |
14 | 2dc285988602 |
15 | 1600914ed84c |
hex | b03dc6fc5fa |
12111211120122 has 12 divisors (see below), whose sum is σ = 26240957426970. Its totient is φ = 4037070373368.
The previous prime is 12111211120117. The next prime is 12111211120153. The reversal of 12111211120122 is 22102111211121.
It is a happy number.
12111211120122 is a `hidden beast` number, since 1 + 211 + 1 + 211 + 120 + 122 = 666.
It can be written as a sum of positive squares in only one way, i.e., 11848678880481 + 262532239641 = 3442191^2 + 512379^2 .
It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 672845062229 = 12111211120122 / (1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 0 + 1 + 2 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 12111211120095 and 12111211120104.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 336422531097 + ... + 336422531132.
Almost surely, 212111211120122 is an apocalyptic number.
12111211120122 is an abundant number, since it is smaller than the sum of its proper divisors (14129746306848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12111211120122 is a wasteful number, since it uses less digits than its factorization.
12111211120122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 672845062237 (or 672845062234 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 18.
Adding to 12111211120122 its reverse (22102111211121), we get a palindrome (34213322331243).
Subtracting 12111211120122 from its reverse (22102111211121), we obtain a palindrome (9990900090999).
The spelling of 12111211120122 in words is "twelve trillion, one hundred eleven billion, two hundred eleven million, one hundred twenty thousand, one hundred twenty-two".
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