Base | Representation |
---|---|
bin | 11011100010011010011100… |
… | …011011010010000101000111 |
3 | 120212211012112100002211112201 |
4 | 123202122130123102011013 |
5 | 111333300101211211442 |
6 | 1105330045233055331 |
7 | 34340030021044054 |
oct | 3342323433220507 |
9 | 525735470084481 |
10 | 121112112210247 |
11 | 356543a3a58014 |
12 | 117004093b7547 |
13 | 5276a91696b52 |
14 | 21c9c0100402b |
15 | e0060d63e7b7 |
hex | 6e269c6d2147 |
121112112210247 has 2 divisors, whose sum is σ = 121112112210248. Its totient is φ = 121112112210246.
The previous prime is 121112112210169. The next prime is 121112112210293. The reversal of 121112112210247 is 742012211211121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121112112210247 - 215 = 121112112177479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121112112210647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556056105123 + 60556056105124.
It is an arithmetic number, because the mean of its divisors is an integer number (60556056105124).
Almost surely, 2121112112210247 is an apocalyptic number.
121112112210247 is a deficient number, since it is larger than the sum of its proper divisors (1).
121112112210247 is an equidigital number, since it uses as much as digits as its factorization.
121112112210247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 28.
Adding to 121112112210247 its reverse (742012211211121), we get a palindrome (863124323421368).
The spelling of 121112112210247 in words is "one hundred twenty-one trillion, one hundred twelve billion, one hundred twelve million, two hundred ten thousand, two hundred forty-seven".
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