1211121253 has 2 divisors, whose sum is σ = 1211121254. Its totient is φ = 1211121252.

The previous prime is 1211121227. The next prime is 1211121257. The reversal of 1211121253 is 3521211121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 902521764 + 308599489 = 30042^2 + 17567^2 .

It is an emirp because it is prime and its reverse (3521211121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1211121253 - 2²¹ = 1209024101 is a prime.

It is a super-3 number, since 3×1211121253³ (a number of 28 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1211121253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211121257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605560626 + 605560627.

It is an arithmetic number, because the mean of its divisors is an integer number (605560627).

Almost surely, 2^1211121253 is an apocalyptic number.

It is an amenable number.

1211121253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211121253 is an equidigital number, since it uses as much as digits as its factorization.

1211121253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 19.

The square root of 1211121253 is about 34801.1674085798. The cubic root of 1211121253 is about 1065.9312838288.

Adding to 1211121253 its reverse (3521211121), we get a palindrome (4732332374).

The spelling of 1211121253 in words is "one billion, two hundred eleven million, one hundred twenty-one thousand, two hundred fifty-three".