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12111220109977 is a prime number
BaseRepresentation
bin1011000000111101110011…
…1110001111001010011001
31120212211011202100002101221
42300033130332033022121
53041412234322004402
641431452343012041
72360002216235632
oct260173476171231
946784152302357
1012111220109977
11394a38101666a
12143729b13a021
1369b110902451
142dc286c48889
151600921c7337
hexb03dcf8f299

12111220109977 has 2 divisors, whose sum is σ = 12111220109978. Its totient is φ = 12111220109976.

The previous prime is 12111220109941. The next prime is 12111220110127. The reversal of 12111220109977 is 77990102211121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9113280230041 + 2997939879936 = 3018821^2 + 1731456^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12111220109977 is a prime.

It is a super-2 number, since 2×121112201099772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12111220109777) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055610054988 + 6055610054989.

It is an arithmetic number, because the mean of its divisors is an integer number (6055610054989).

Almost surely, 212111220109977 is an apocalyptic number.

It is an amenable number.

12111220109977 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111220109977 is an equidigital number, since it uses as much as digits as its factorization.

12111220109977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31752, while the sum is 43.

The spelling of 12111220109977 in words is "twelve trillion, one hundred eleven billion, two hundred twenty million, one hundred nine thousand, nine hundred seventy-seven".