Base | Representation |
---|---|
bin | 1011000000111101110011… |
… | …1110001111001100101111 |
3 | 1120212211011202100002121111 |
4 | 2300033130332033030233 |
5 | 3041412234322011002 |
6 | 41431452343012451 |
7 | 2360002216236235 |
oct | 260173476171457 |
9 | 46784152302544 |
10 | 12111220110127 |
11 | 394a381016796 |
12 | 143729b13a127 |
13 | 69b110902538 |
14 | 2dc286c48955 |
15 | 1600921c73d7 |
hex | b03dcf8f32f |
12111220110127 has 2 divisors, whose sum is σ = 12111220110128. Its totient is φ = 12111220110126.
The previous prime is 12111220109977. The next prime is 12111220110161. The reversal of 12111220110127 is 72101102211121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12111220110127 - 211 = 12111220108079 is a prime.
It is a super-2 number, since 2×121112201101272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12111220110098 and 12111220110107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111220110727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055610055063 + 6055610055064.
It is an arithmetic number, because the mean of its divisors is an integer number (6055610055064).
Almost surely, 212111220110127 is an apocalyptic number.
12111220110127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111220110127 is an equidigital number, since it uses as much as digits as its factorization.
12111220110127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 12111220110127 its reverse (72101102211121), we get a palindrome (84212322321248).
The spelling of 12111220110127 in words is "twelve trillion, one hundred eleven billion, two hundred twenty million, one hundred ten thousand, one hundred twenty-seven".
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