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121113143 is a prime number
BaseRepresentation
bin1110011100000…
…00101000110111
322102220011222222
413032000220313
5222001110033
620003512555
73000305354
oct716005067
9272804888
10121113143
1162402108
123468875b
131c1267a8
141212962b
15a975598
hex7380a37

121113143 has 2 divisors, whose sum is σ = 121113144. Its totient is φ = 121113142.

The previous prime is 121113137. The next prime is 121113199. The reversal of 121113143 is 341311121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121113143 - 26 = 121113079 is a prime.

It is a Chen prime.

It is a zygodrome in base 5.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121115143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556571 + 60556572.

It is an arithmetic number, because the mean of its divisors is an integer number (60556572).

Almost surely, 2121113143 is an apocalyptic number.

121113143 is a deficient number, since it is larger than the sum of its proper divisors (1).

121113143 is an equidigital number, since it uses as much as digits as its factorization.

121113143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72, while the sum is 17.

The square root of 121113143 is about 11005.1416619687. The cubic root of 121113143 is about 494.7628602578.

Adding to 121113143 its reverse (341311121), we get a palindrome (462424264).

The spelling of 121113143 in words is "one hundred twenty-one million, one hundred thirteen thousand, one hundred forty-three".