Base | Representation |
---|---|
bin | 111000011001011101… |
… | …0001010110111001011 |
3 | 102120121120211201111022 |
4 | 1300302322022313023 |
5 | 3441014434201211 |
6 | 131345540023055 |
7 | 11515204106522 |
oct | 1606272126713 |
9 | 376546751438 |
10 | 121113193931 |
11 | 47400271204 |
12 | 1b580691a8b |
13 | b561a075c2 |
14 | 5c0d11b4b9 |
15 | 323ca95bdb |
hex | 1c32e8adcb |
121113193931 has 2 divisors, whose sum is σ = 121113193932. Its totient is φ = 121113193930.
The previous prime is 121113193921. The next prime is 121113193933. The reversal of 121113193931 is 139391311121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121113193931 is a prime.
It is a super-2 number, since 2×1211131939312 (a number of 23 digits) contains 22 as substring.
Together with 121113193933, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 121113193891 and 121113193900.
It is not a weakly prime, because it can be changed into another prime (121113193933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556596965 + 60556596966.
It is an arithmetic number, because the mean of its divisors is an integer number (60556596966).
Almost surely, 2121113193931 is an apocalyptic number.
121113193931 is a deficient number, since it is larger than the sum of its proper divisors (1).
121113193931 is an equidigital number, since it uses as much as digits as its factorization.
121113193931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4374, while the sum is 35.
The spelling of 121113193931 in words is "one hundred twenty-one billion, one hundred thirteen million, one hundred ninety-three thousand, nine hundred thirty-one".
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