Base | Representation |
---|---|
bin | 111000011001011101… |
… | …0001100110101011101 |
3 | 102120121120212010120122 |
4 | 1300302322030311131 |
5 | 3441014434431023 |
6 | 131345540124325 |
7 | 11515204142216 |
oct | 1606272146535 |
9 | 376546763518 |
10 | 121113202013 |
11 | 47400277291 |
12 | 1b5806966a5 |
13 | b561a0b19b |
14 | 5c0d12040d |
15 | 323ca982c8 |
hex | 1c32e8cd5d |
121113202013 has 2 divisors, whose sum is σ = 121113202014. Its totient is φ = 121113202012.
The previous prime is 121113202009. The next prime is 121113202057. The reversal of 121113202013 is 310202311121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115571441764 + 5541760249 = 339958^2 + 74443^2 .
It is an emirp because it is prime and its reverse (310202311121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121113202013 - 22 = 121113202009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121113201982 and 121113202000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121113205013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556601006 + 60556601007.
It is an arithmetic number, because the mean of its divisors is an integer number (60556601007).
Almost surely, 2121113202013 is an apocalyptic number.
It is an amenable number.
121113202013 is a deficient number, since it is larger than the sum of its proper divisors (1).
121113202013 is an equidigital number, since it uses as much as digits as its factorization.
121113202013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 121113202013 its reverse (310202311121), we get a palindrome (431315513134).
The spelling of 121113202013 in words is "one hundred twenty-one billion, one hundred thirteen million, two hundred two thousand, thirteen".
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