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1211132323033 is a prime number
BaseRepresentation
bin10001100111111101000…
…111001010010011011001
311021210010220010201021221
4101213331013022103121
5124320344333314113
62324215252532041
7153333662613223
oct21477507122331
94253126121257
101211132323033
11427702693166
12176885921021
138a294a622b9
1442894c01413
15217871b698d
hex119fd1ca4d9

1211132323033 has 2 divisors, whose sum is σ = 1211132323034. Its totient is φ = 1211132323032.

The previous prime is 1211132322937. The next prime is 1211132323081. The reversal of 1211132323033 is 3303232311121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1191147411609 + 19984911424 = 1091397^2 + 141368^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211132323033 - 225 = 1211098768601 is a prime.

It is a super-2 number, since 2×12111323230332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211132322989 and 1211132323007.

It is not a weakly prime, because it can be changed into another prime (1211132353033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605566161516 + 605566161517.

It is an arithmetic number, because the mean of its divisors is an integer number (605566161517).

Almost surely, 21211132323033 is an apocalyptic number.

It is an amenable number.

1211132323033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211132323033 is an equidigital number, since it uses as much as digits as its factorization.

1211132323033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1211132323033 its reverse (3303232311121), we get a palindrome (4514364634154).

The spelling of 1211132323033 in words is "one trillion, two hundred eleven billion, one hundred thirty-two million, three hundred twenty-three thousand, thirty-three".