Base | Representation |
---|---|
bin | 1011000000111110001111… |
… | …0001001110100001100111 |
3 | 1120212211110200220102012101 |
4 | 2300033203301032201213 |
5 | 3041413003014440012 |
6 | 41431511535032531 |
7 | 2360005102413664 |
oct | 260174361164147 |
9 | 46784420812171 |
10 | 12111334140007 |
11 | 394a42a420063 |
12 | 143731136b747 |
13 | 69b12b418c3b |
14 | 2dc29804ca6b |
15 | 16009c1edd57 |
hex | b03e3c4e867 |
12111334140007 has 2 divisors, whose sum is σ = 12111334140008. Its totient is φ = 12111334140006.
The previous prime is 12111334139987. The next prime is 12111334140013. The reversal of 12111334140007 is 70004143311121.
12111334140007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12111334140007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111334140097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055667070003 + 6055667070004.
It is an arithmetic number, because the mean of its divisors is an integer number (6055667070004).
Almost surely, 212111334140007 is an apocalyptic number.
12111334140007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111334140007 is an equidigital number, since it uses as much as digits as its factorization.
12111334140007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 12111334140007 its reverse (70004143311121), we get a palindrome (82115477451128).
The spelling of 12111334140007 in words is "twelve trillion, one hundred eleven billion, three hundred thirty-four million, one hundred forty thousand, seven".
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