Base | Representation |
---|---|
bin | 1011000000111110011110… |
… | …1100100101000001100011 |
3 | 1120212211122021212222200212 |
4 | 2300033213230211001203 |
5 | 3041413121401432212 |
6 | 41431522251204335 |
7 | 2360006532442664 |
oct | 260174754450143 |
9 | 46784567788625 |
10 | 12111400030307 |
11 | 394a463634456 |
12 | 143732b4466ab |
13 | 69b13bc78c96 |
14 | 2dc2a2ac136b |
15 | 1600a2db6e22 |
hex | b03e7b25063 |
12111400030307 has 2 divisors, whose sum is σ = 12111400030308. Its totient is φ = 12111400030306.
The previous prime is 12111400030241. The next prime is 12111400030313. The reversal of 12111400030307 is 70303000411121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12111400030307 - 210 = 12111400029283 is a prime.
It is a super-3 number, since 3×121114000303073 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12111400030357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055700015153 + 6055700015154.
It is an arithmetic number, because the mean of its divisors is an integer number (6055700015154).
Almost surely, 212111400030307 is an apocalyptic number.
12111400030307 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111400030307 is an equidigital number, since it uses as much as digits as its factorization.
12111400030307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 12111400030307 its reverse (70303000411121), we get a palindrome (82414400441428).
The spelling of 12111400030307 in words is "twelve trillion, one hundred eleven billion, four hundred million, thirty thousand, three hundred seven".
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