Base | Representation |
---|---|
bin | 1011000001000000101110… |
… | …0100111101001011100001 |
3 | 1120212220012020121211011102 |
4 | 2300100023210331023201 |
5 | 3041420340003334443 |
6 | 41432102113524145 |
7 | 2360030462264201 |
oct | 260201344751341 |
9 | 46786166554142 |
10 | 12112002011873 |
11 | 394a742416085 |
12 | 1437478b73655 |
13 | 69b2068b97aa |
14 | 2dc31ca22401 |
15 | 1600dab76cb8 |
hex | b040b93d2e1 |
12112002011873 has 2 divisors, whose sum is σ = 12112002011874. Its totient is φ = 12112002011872.
The previous prime is 12112002011869. The next prime is 12112002011927. The reversal of 12112002011873 is 37811020021121.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12104672597329 + 7329414544 = 3479177^2 + 85612^2 .
It is a cyclic number.
It is not a de Polignac number, because 12112002011873 - 22 = 12112002011869 is a prime.
It is not a weakly prime, because it can be changed into another prime (12112002011173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056001005936 + 6056001005937.
It is an arithmetic number, because the mean of its divisors is an integer number (6056001005937).
Almost surely, 212112002011873 is an apocalyptic number.
It is an amenable number.
12112002011873 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112002011873 is an equidigital number, since it uses as much as digits as its factorization.
12112002011873 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 29.
Adding to 12112002011873 its reverse (37811020021121), we get a palindrome (49923022032994).
The spelling of 12112002011873 in words is "twelve trillion, one hundred twelve billion, two million, eleven thousand, eight hundred seventy-three".
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