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1211201112013 = 5920528832407
BaseRepresentation
bin10001101000000001001…
…101100100011111001101
311021210022200120120000221
4101220001031210133031
5124321014441041023
62324230151151341
7153335456404204
oct21500115443715
94253280516027
101211201112013
114277384a7362
121768a4975551
138a2a6098839
144289ddca23b
152178d25385d
hex11a013647cd

1211201112013 has 4 divisors (see below), whose sum is σ = 1231729944480. Its totient is φ = 1190672279548.

The previous prime is 1211201111971. The next prime is 1211201112019. The reversal of 1211201112013 is 3102111021121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211201112013 - 213 = 1211201103821 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211201112019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10264416145 + ... + 10264416262.

It is an arithmetic number, because the mean of its divisors is an integer number (307932486120).

Almost surely, 21211201112013 is an apocalyptic number.

It is an amenable number.

1211201112013 is a deficient number, since it is larger than the sum of its proper divisors (20528832467).

1211201112013 is an equidigital number, since it uses as much as digits as its factorization.

1211201112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20528832466.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 1211201112013 its reverse (3102111021121), we get a palindrome (4313312133134).

The spelling of 1211201112013 in words is "one trillion, two hundred eleven billion, two hundred one million, one hundred twelve thousand, thirteen".

Divisors: 1 59 20528832407 1211201112013