1211209999903 has 2 divisors, whose sum is σ = 1211209999904. Its totient is φ = 1211209999902.

The previous prime is 1211209999849. The next prime is 1211209999913. The reversal of 1211209999903 is 3099999021121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1211209999903 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211209999913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605604999951 + 605604999952.

It is an arithmetic number, because the mean of its divisors is an integer number (605604999952).

Almost surely, 2^{1211209999903} is an apocalyptic number.

1211209999903 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211209999903 is an equidigital number, since it uses as much as digits as its factorization.

1211209999903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 708588, while the sum is 55.

The spelling of 1211209999903 in words is "one trillion, two hundred eleven billion, two hundred nine million, nine hundred ninety-nine thousand, nine hundred three".