Base | Representation |
---|---|
bin | 11011100010100010101110… |
… | …010011001000111011100011 |
3 | 120212212001110212210221122201 |
4 | 123202202232103020323203 |
5 | 111333421303003000344 |
6 | 1105334115320114031 |
7 | 34340463225026533 |
oct | 3342425623107343 |
9 | 525761425727581 |
10 | 121121002000099 |
11 | 35658146013782 |
12 | 1170208a605917 |
13 | 527787a36a22a |
14 | 21ca40592b4c3 |
15 | e0097dceb4d4 |
hex | 6e28ae4c8ee3 |
121121002000099 has 2 divisors, whose sum is σ = 121121002000100. Its totient is φ = 121121002000098.
The previous prime is 121121002000067. The next prime is 121121002000127. The reversal of 121121002000099 is 990000200121121.
It is an a-pointer prime, because the next prime (121121002000127) can be obtained adding 121121002000099 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121121002000099 - 25 = 121121002000067 is a prime.
It is not a weakly prime, because it can be changed into another prime (121121002000199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560501000049 + 60560501000050.
It is an arithmetic number, because the mean of its divisors is an integer number (60560501000050).
Almost surely, 2121121002000099 is an apocalyptic number.
121121002000099 is a deficient number, since it is larger than the sum of its proper divisors (1).
121121002000099 is an equidigital number, since it uses as much as digits as its factorization.
121121002000099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 28.
The spelling of 121121002000099 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, two million, ninety-nine", and thus it is an aban number.
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