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1211211200053 is a prime number
BaseRepresentation
bin10001101000000001110…
…100000011011000110101
311021210100101120002020001
4101220001310003120311
5124321030031400203
62324231151311301
7153335641221331
oct21500164033065
94253311502201
101211211200053
11427743167688
121768a821b531
138a2a81bb4aa
14428a14947c1
152178e09791d
hex11a01d03635

1211211200053 has 2 divisors, whose sum is σ = 1211211200054. Its totient is φ = 1211211200052.

The previous prime is 1211211200041. The next prime is 1211211200063. The reversal of 1211211200053 is 3500021121121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 707874870609 + 503336329444 = 841353^2 + 709462^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211211200053 - 229 = 1210674329141 is a prime.

It is a super-2 number, since 2×12112112000532 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1211211200053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211211200063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605605600026 + 605605600027.

It is an arithmetic number, because the mean of its divisors is an integer number (605605600027).

Almost surely, 21211211200053 is an apocalyptic number.

It is an amenable number.

1211211200053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211211200053 is an equidigital number, since it uses as much as digits as its factorization.

1211211200053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 1211211200053 its reverse (3500021121121), we get a palindrome (4711232321174).

The spelling of 1211211200053 in words is "one trillion, two hundred eleven billion, two hundred eleven million, two hundred thousand, fifty-three".