Base | Representation |
---|---|
bin | 111000011001101110… |
… | …0010000110101100100 |
3 | 102120122012122210020222 |
4 | 1300303130100311210 |
5 | 3441024231200200 |
6 | 131350455343512 |
7 | 11515343062142 |
oct | 1606334206544 |
9 | 376565583228 |
10 | 121122131300 |
11 | 47405315a65 |
12 | 1b583681b98 |
13 | b5638165a1 |
14 | 5c103a6592 |
15 | 323d75dd85 |
hex | 1c33710d64 |
121122131300 has 18 divisors (see below), whose sum is σ = 262835025138. Its totient is φ = 48448852480.
The previous prime is 121122131297. The next prime is 121122131303. The reversal of 121122131300 is 3131221121.
It is an interprime number because it is at equal distance from previous prime (121122131297) and next prime (121122131303).
It can be written as a sum of positive squares in 3 ways, for example, as 39742017316 + 81380113984 = 199354^2 + 285272^2 .
It is a super-3 number, since 3×1211221313003 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (121122131303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 605610557 + ... + 605610756.
It is an arithmetic number, because the mean of its divisors is an integer number (14601945841).
Almost surely, 2121122131300 is an apocalyptic number.
121122131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121122131300 is an abundant number, since it is smaller than the sum of its proper divisors (141712893838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121122131300 is a wasteful number, since it uses less digits than its factorization.
121122131300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1211221327 (or 1211221320 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 121122131300 its reverse (3131221121), we get a palindrome (124253352421).
It can be divided in two parts, 12112 and 2131300, that added together give a palindrome (2143412).
The spelling of 121122131300 in words is "one hundred twenty-one billion, one hundred twenty-two million, one hundred thirty-one thousand, three hundred".
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