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121122413233 is a prime number
BaseRepresentation
bin111000011001101110…
…1010101101010110001
3102120122020012002222221
41300303131111222301
53441024314210413
6131350505401041
711515345345123
oct1606335255261
9376566162887
10121122413233
1147405498868
121b583799181
13b5638b4a03
145c1043b213
15323d7b768d
hex1c33755ab1

121122413233 has 2 divisors, whose sum is σ = 121122413234. Its totient is φ = 121122413232.

The previous prime is 121122413197. The next prime is 121122413261. The reversal of 121122413233 is 332314221121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78880654449 + 42241758784 = 280857^2 + 205528^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121122413233 is a prime.

It is a super-2 number, since 2×1211224132332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121122413198 and 121122413207.

It is not a weakly prime, because it can be changed into another prime (121122411233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561206616 + 60561206617.

It is an arithmetic number, because the mean of its divisors is an integer number (60561206617).

Almost surely, 2121122413233 is an apocalyptic number.

It is an amenable number.

121122413233 is a deficient number, since it is larger than the sum of its proper divisors (1).

121122413233 is an equidigital number, since it uses as much as digits as its factorization.

121122413233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1728, while the sum is 25.

Adding to 121122413233 its reverse (332314221121), we get a palindrome (453436634354).

The spelling of 121122413233 in words is "one hundred twenty-one billion, one hundred twenty-two million, four hundred thirteen thousand, two hundred thirty-three".