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121123031331223 is a prime number
BaseRepresentation
bin11011100010100100100111…
…010000011011000110010111
3120212212020201022100122121201
4123202210213100123012113
5111333434432010044343
61105335052531453331
734340564426043025
oct3342444720330627
9525766638318551
10121123031331223
1135658a97574239
1211702556157247
135277b11913c8c
1421ca55925d715
15e00a4c05494d
hex6e292741b197

121123031331223 has 2 divisors, whose sum is σ = 121123031331224. Its totient is φ = 121123031331222.

The previous prime is 121123031331217. The next prime is 121123031331227. The reversal of 121123031331223 is 322133130321121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121123031331223 - 217 = 121123031200151 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121123031331191 and 121123031331200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121123031331227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561515665611 + 60561515665612.

It is an arithmetic number, because the mean of its divisors is an integer number (60561515665612).

Almost surely, 2121123031331223 is an apocalyptic number.

121123031331223 is a deficient number, since it is larger than the sum of its proper divisors (1).

121123031331223 is an equidigital number, since it uses as much as digits as its factorization.

121123031331223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 121123031331223 its reverse (322133130321121), we get a palindrome (443256161652344).

The spelling of 121123031331223 in words is "one hundred twenty-one trillion, one hundred twenty-three billion, thirty-one million, three hundred thirty-one thousand, two hundred twenty-three".