1211231310049 has 2 divisors, whose sum is σ = 1211231310050. Its totient is φ = 1211231310048.

The previous prime is 1211231310019. The next prime is 1211231310077. The reversal of 1211231310049 is 9400131321121.

It is an a-pointer prime, because the next prime (1211231310077) can be obtained adding 1211231310049 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1066045925025 + 145185385024 = 1032495^2 + 381032^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211231310049 - 2⁵ = 1211231310017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1211231309999 and 1211231310026.

It is not a weakly prime, because it can be changed into another prime (1211231310019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605615655024 + 605615655025.

It is an arithmetic number, because the mean of its divisors is an integer number (605615655025).

Almost surely, 2^{1211231310049} is an apocalyptic number.

It is an amenable number.

1211231310049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211231310049 is an equidigital number, since it uses as much as digits as its factorization.

1211231310049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 1211231310049 in words is "one trillion, two hundred eleven billion, two hundred thirty-one million, three hundred ten thousand, forty-nine".