Base | Representation |
---|---|
bin | 10001101000000011000… |
… | …100101010100101010001 |
3 | 11021210101212022200221221 |
4 | 101220003010222211101 |
5 | 124321100434111423 |
6 | 2324233224245041 |
7 | 153336315643666 |
oct | 21500304524521 |
9 | 4253355280857 |
10 | 1211232332113 |
11 | 4277540904a1 |
12 | 1768b3310781 |
13 | 8a2ac6a9c7b |
14 | 428a41d5a6d |
15 | 21790d6de5d |
hex | 11a0312a951 |
1211232332113 has 2 divisors, whose sum is σ = 1211232332114. Its totient is φ = 1211232332112.
The previous prime is 1211232332077. The next prime is 1211232332129. The reversal of 1211232332113 is 3112332321121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 937930267024 + 273302065089 = 968468^2 + 522783^2 .
It is an emirp because it is prime and its reverse (3112332321121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211232332113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1211232339113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605616166056 + 605616166057.
It is an arithmetic number, because the mean of its divisors is an integer number (605616166057).
Almost surely, 21211232332113 is an apocalyptic number.
It is an amenable number.
1211232332113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211232332113 is an equidigital number, since it uses as much as digits as its factorization.
1211232332113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 25.
Adding to 1211232332113 its reverse (3112332321121), we get a palindrome (4323564653234).
The spelling of 1211232332113 in words is "one trillion, two hundred eleven billion, two hundred thirty-two million, three hundred thirty-two thousand, one hundred thirteen".
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