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121130013012361 is a prime number
BaseRepresentation
bin11011100010101011000111…
…011001011011000110001001
3120212212220201212121210122121
4123202223013121123012021
5111334043231312343421
61105342205413251241
734341232433254363
oct3342530731330611
9525786655553577
10121130013012361
1135660a4a546651
1211703984333b21
1352786851a4a52
1421caa1c5abd33
15e00d09e50d41
hex6e2ac765b189

121130013012361 has 2 divisors, whose sum is σ = 121130013012362. Its totient is φ = 121130013012360.

The previous prime is 121130013012319. The next prime is 121130013012509. The reversal of 121130013012361 is 163210310031121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71727670469961 + 49402342542400 = 8469219^2 + 7028680^2 .

It is a cyclic number.

It is not a de Polignac number, because 121130013012361 - 211 = 121130013010313 is a prime.

It is not a weakly prime, because it can be changed into another prime (121130013312361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565006506180 + 60565006506181.

It is an arithmetic number, because the mean of its divisors is an integer number (60565006506181).

Almost surely, 2121130013012361 is an apocalyptic number.

It is an amenable number.

121130013012361 is a deficient number, since it is larger than the sum of its proper divisors (1).

121130013012361 is an equidigital number, since it uses as much as digits as its factorization.

121130013012361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 121130013012361 its reverse (163210310031121), we get a palindrome (284340323043482).

The spelling of 121130013012361 in words is "one hundred twenty-one trillion, one hundred thirty billion, thirteen million, twelve thousand, three hundred sixty-one".