Base | Representation |
---|---|
bin | 11011100010101011000111… |
… | …011001011011000110001001 |
3 | 120212212220201212121210122121 |
4 | 123202223013121123012021 |
5 | 111334043231312343421 |
6 | 1105342205413251241 |
7 | 34341232433254363 |
oct | 3342530731330611 |
9 | 525786655553577 |
10 | 121130013012361 |
11 | 35660a4a546651 |
12 | 11703984333b21 |
13 | 52786851a4a52 |
14 | 21caa1c5abd33 |
15 | e00d09e50d41 |
hex | 6e2ac765b189 |
121130013012361 has 2 divisors, whose sum is σ = 121130013012362. Its totient is φ = 121130013012360.
The previous prime is 121130013012319. The next prime is 121130013012509. The reversal of 121130013012361 is 163210310031121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 71727670469961 + 49402342542400 = 8469219^2 + 7028680^2 .
It is a cyclic number.
It is not a de Polignac number, because 121130013012361 - 211 = 121130013010313 is a prime.
It is not a weakly prime, because it can be changed into another prime (121130013312361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565006506180 + 60565006506181.
It is an arithmetic number, because the mean of its divisors is an integer number (60565006506181).
Almost surely, 2121130013012361 is an apocalyptic number.
It is an amenable number.
121130013012361 is a deficient number, since it is larger than the sum of its proper divisors (1).
121130013012361 is an equidigital number, since it uses as much as digits as its factorization.
121130013012361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 121130013012361 its reverse (163210310031121), we get a palindrome (284340323043482).
The spelling of 121130013012361 in words is "one hundred twenty-one trillion, one hundred thirty billion, thirteen million, twelve thousand, three hundred sixty-one".
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