Base | Representation |
---|---|
bin | 10001101000000111011… |
… | …101110011100000010111 |
3 | 11021210121000000000000001 |
4 | 101220013131303200113 |
5 | 124321223320444002 |
6 | 2324244420032131 |
7 | 153341202244633 |
oct | 21500735634027 |
9 | 4253530000001 |
10 | 1211306031127 |
11 | 427791748675 |
12 | 176913b32647 |
13 | 8a2c1a4235a |
14 | 428adcdbdc3 |
15 | 2179757aa87 |
hex | 11a07773817 |
1211306031127 has 2 divisors, whose sum is σ = 1211306031128. Its totient is φ = 1211306031126.
The previous prime is 1211306031101. The next prime is 1211306031137. The reversal of 1211306031127 is 7211306031121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211306031127 - 27 = 1211306030999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211306031095 and 1211306031104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211306031137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605653015563 + 605653015564.
It is an arithmetic number, because the mean of its divisors is an integer number (605653015564).
Almost surely, 21211306031127 is an apocalyptic number.
1211306031127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211306031127 is an equidigital number, since it uses as much as digits as its factorization.
1211306031127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
The spelling of 1211306031127 in words is "one trillion, two hundred eleven billion, three hundred six million, thirty-one thousand, one hundred twenty-seven".
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