Search a number
-
+
121131019105807 is a prime number
BaseRepresentation
bin11011100010101100000011…
…010111010111011000001111
3120212220000022222202122101211
4123202230003113113120033
5111334102311342341212
61105342453313315251
734341266401024414
oct3342540327273017
9525800288678354
10121131019105807
1135661416451537
1211704005265b27
1352787b5766609
1421caab606410b
15e00d684379a7
hex6e2b035d760f

121131019105807 has 2 divisors, whose sum is σ = 121131019105808. Its totient is φ = 121131019105806.

The previous prime is 121131019105769. The next prime is 121131019105843. The reversal of 121131019105807 is 708501910131121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121131019105807 - 215 = 121131019073039 is a prime.

It is a super-2 number, since 2×1211310191058072 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 121131019105807.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121131019105007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565509552903 + 60565509552904.

It is an arithmetic number, because the mean of its divisors is an integer number (60565509552904).

Almost surely, 2121131019105807 is an apocalyptic number.

121131019105807 is a deficient number, since it is larger than the sum of its proper divisors (1).

121131019105807 is an equidigital number, since it uses as much as digits as its factorization.

121131019105807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 40.

Adding to 121131019105807 its reverse (708501910131121), we get a palindrome (829632929236928).

The spelling of 121131019105807 in words is "one hundred twenty-one trillion, one hundred thirty-one billion, nineteen million, one hundred five thousand, eight hundred seven".