Base | Representation |
---|---|
bin | 10001101000000111101… |
… | …110000101110010001101 |
3 | 11021210121022000220012121 |
4 | 101220013232011302031 |
5 | 124321230414102201 |
6 | 2324245051332541 |
7 | 153341253445333 |
oct | 21500756056215 |
9 | 4253538026177 |
10 | 1211310300301 |
11 | 4277940a4112 |
12 | 176915451151 |
13 | 8a2c28a85aa |
14 | 428b06cdb53 |
15 | 21797b209a1 |
hex | 11a07b85c8d |
1211310300301 has 2 divisors, whose sum is σ = 1211310300302. Its totient is φ = 1211310300300.
The previous prime is 1211310300289. The next prime is 1211310300311. The reversal of 1211310300301 is 1030030131121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1080030170025 + 131280130276 = 1039245^2 + 362326^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211310300301 - 225 = 1211276745869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211310300311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605655150150 + 605655150151.
It is an arithmetic number, because the mean of its divisors is an integer number (605655150151).
Almost surely, 21211310300301 is an apocalyptic number.
It is an amenable number.
1211310300301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211310300301 is an equidigital number, since it uses as much as digits as its factorization.
1211310300301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1211310300301 its reverse (1030030131121), we get a palindrome (2241340431422).
The spelling of 1211310300301 in words is "one trillion, two hundred eleven billion, three hundred ten million, three hundred thousand, three hundred one".
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