Base | Representation |
---|---|
bin | 10110100011111111… |
… | …10110100100100101 |
3 | 1011021011221210221002 |
4 | 23101333312210211 |
5 | 144301424030313 |
6 | 5321550003045 |
7 | 606113514251 |
oct | 132177664445 |
9 | 34234853832 |
10 | 12113111333 |
11 | 5156598914 |
12 | 24207a6485 |
13 | 11b07190cb |
14 | 82ca63261 |
15 | 4ad665058 |
hex | 2d1ff6925 |
12113111333 has 2 divisors, whose sum is σ = 12113111334. Its totient is φ = 12113111332.
The previous prime is 12113111293. The next prime is 12113111347. The reversal of 12113111333 is 33311131121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11587876609 + 525234724 = 107647^2 + 22918^2 .
It is an emirp because it is prime and its reverse (33311131121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12113111333 - 228 = 11844675877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12113111533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056555666 + 6056555667.
It is an arithmetic number, because the mean of its divisors is an integer number (6056555667).
Almost surely, 212113111333 is an apocalyptic number.
It is an amenable number.
12113111333 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113111333 is an equidigital number, since it uses as much as digits as its factorization.
12113111333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 162, while the sum is 20.
Adding to 12113111333 its reverse (33311131121), we get a palindrome (45424242454).
The spelling of 12113111333 in words is "twelve billion, one hundred thirteen million, one hundred eleven thousand, three hundred thirty-three".
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