Base | Representation |
---|---|
bin | 1011000001000100110111… |
… | …1000011101100010111111 |
3 | 1120220000001202211002012201 |
4 | 2300101031320131202333 |
5 | 3041430124242441224 |
6 | 41432404332412331 |
7 | 2360100160513603 |
oct | 260211570354277 |
9 | 46800052732181 |
10 | 12113114421439 |
11 | 3950163336929 |
12 | 14377296170a7 |
13 | 69b3531c39c5 |
14 | 2dc3c6671503 |
15 | 16015365ea44 |
hex | b044de1d8bf |
12113114421439 has 2 divisors, whose sum is σ = 12113114421440. Its totient is φ = 12113114421438.
The previous prime is 12113114421409. The next prime is 12113114421451. The reversal of 12113114421439 is 93412441131121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12113114421439 - 237 = 11975675467967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12113114421398 and 12113114421407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12113114421409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056557210719 + 6056557210720.
It is an arithmetic number, because the mean of its divisors is an integer number (6056557210720).
Almost surely, 212113114421439 is an apocalyptic number.
12113114421439 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113114421439 is an equidigital number, since it uses as much as digits as its factorization.
12113114421439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20736, while the sum is 37.
The spelling of 12113114421439 in words is "twelve trillion, one hundred thirteen billion, one hundred fourteen million, four hundred twenty-one thousand, four hundred thirty-nine".
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