Base | Representation |
---|---|
bin | 111000011001111111… |
… | …0110111010111100111 |
3 | 102120122211201121221200 |
4 | 1300303332313113213 |
5 | 3441034041431043 |
6 | 131351422013543 |
7 | 11515513141326 |
oct | 1606376672747 |
9 | 376584647850 |
10 | 121131202023 |
11 | 4740a450a27 |
12 | 1b5867172b3 |
13 | b565671190 |
14 | 5c116880bd |
15 | 323e4517d3 |
hex | 1c33fb75e7 |
121131202023 has 48 divisors (see below), whose sum is σ = 197110839744. Its totient is φ = 71122867200.
The previous prime is 121131202019. The next prime is 121131202109. The reversal of 121131202023 is 320202131121.
It is not a de Polignac number, because 121131202023 - 22 = 121131202019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121131201987 and 121131202005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121131203023) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1022965 + ... + 1135217.
It is an arithmetic number, because the mean of its divisors is an integer number (4106475828).
Almost surely, 2121131202023 is an apocalyptic number.
121131202023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
121131202023 is a deficient number, since it is larger than the sum of its proper divisors (75979637721).
121131202023 is a wasteful number, since it uses less digits than its factorization.
121131202023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 112696 (or 112693 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 121131202023 its reverse (320202131121), we get a palindrome (441333333144).
The spelling of 121131202023 in words is "one hundred twenty-one billion, one hundred thirty-one million, two hundred two thousand, twenty-three".
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