Base | Representation |
---|---|
bin | 111000011001111111… |
… | …0110111011000111101 |
3 | 102120122211201122001212 |
4 | 1300303332313120331 |
5 | 3441034041431414 |
6 | 131351422014205 |
7 | 11515513141511 |
oct | 1606376673075 |
9 | 376584648055 |
10 | 121131202109 |
11 | 4740a450aa5 |
12 | 1b586717365 |
13 | b565671228 |
14 | 5c11688141 |
15 | 323e45183e |
hex | 1c33fb763d |
121131202109 has 2 divisors, whose sum is σ = 121131202110. Its totient is φ = 121131202108.
The previous prime is 121131202019. The next prime is 121131202139. The reversal of 121131202109 is 901202131121.
Together with previous prime (121131202019) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 117702514084 + 3428688025 = 343078^2 + 58555^2 .
It is an emirp because it is prime and its reverse (901202131121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121131202109 - 232 = 116836234813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121131202139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565601054 + 60565601055.
It is an arithmetic number, because the mean of its divisors is an integer number (60565601055).
Almost surely, 2121131202109 is an apocalyptic number.
It is an amenable number.
121131202109 is a deficient number, since it is larger than the sum of its proper divisors (1).
121131202109 is an equidigital number, since it uses as much as digits as its factorization.
121131202109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 121131202109 in words is "one hundred twenty-one billion, one hundred thirty-one million, two hundred two thousand, one hundred nine".
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