Base | Representation |
---|---|
bin | 11011100010101100001110… |
… | …010010010100001001000011 |
3 | 120212220000210202112110101121 |
4 | 123202230032102110021003 |
5 | 111334103200244044303 |
6 | 1105342523420413111 |
7 | 34341304054305301 |
oct | 3342541622241103 |
9 | 525800722473347 |
10 | 121131202331203 |
11 | 356614aa917489 |
12 | 117040566a7197 |
13 | 52788146c95cc |
14 | 21caad251b271 |
15 | e00d7957b9bd |
hex | 6e2b0e494243 |
121131202331203 has 2 divisors, whose sum is σ = 121131202331204. Its totient is φ = 121131202331202.
The previous prime is 121131202331197. The next prime is 121131202331213. The reversal of 121131202331203 is 302133202131121.
It is a weak prime.
It is an emirp because it is prime and its reverse (302133202131121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121131202331203 - 229 = 121130665460291 is a prime.
It is not a weakly prime, because it can be changed into another prime (121131202331213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60565601165601 + 60565601165602.
It is an arithmetic number, because the mean of its divisors is an integer number (60565601165602).
Almost surely, 2121131202331203 is an apocalyptic number.
121131202331203 is a deficient number, since it is larger than the sum of its proper divisors (1).
121131202331203 is an equidigital number, since it uses as much as digits as its factorization.
121131202331203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 121131202331203 its reverse (302133202131121), we get a palindrome (423264404462324).
The spelling of 121131202331203 in words is "one hundred twenty-one trillion, one hundred thirty-one billion, two hundred two million, three hundred thirty-one thousand, two hundred three".
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