Base | Representation |
---|---|
bin | 10001101000000111110… |
… | …100111111100110111101 |
3 | 11021210121102102211122222 |
4 | 101220013310333212331 |
5 | 124321231400010023 |
6 | 2324245154215125 |
7 | 153341305023425 |
oct | 21500764774675 |
9 | 4253542384588 |
10 | 1211312110013 |
11 | 42779511a845 |
12 | 176915b844a5 |
13 | 8a2c3090225 |
14 | 428b0a41485 |
15 | 21797d7bcc8 |
hex | 11a07d3f9bd |
1211312110013 has 2 divisors, whose sum is σ = 1211312110014. Its totient is φ = 1211312110012.
The previous prime is 1211312109979. The next prime is 1211312110033. The reversal of 1211312110013 is 3100112131121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1174921587844 + 36390522169 = 1083938^2 + 190763^2 .
It is an emirp because it is prime and its reverse (3100112131121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211312110013 - 28 = 1211312109757 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211312109973 and 1211312110000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211312110033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605656055006 + 605656055007.
It is an arithmetic number, because the mean of its divisors is an integer number (605656055007).
Almost surely, 21211312110013 is an apocalyptic number.
It is an amenable number.
1211312110013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211312110013 is an equidigital number, since it uses as much as digits as its factorization.
1211312110013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1211312110013 its reverse (3100112131121), we get a palindrome (4311424241134).
The spelling of 1211312110013 in words is "one trillion, two hundred eleven billion, three hundred twelve million, one hundred ten thousand, thirteen".
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