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12113130221981 is a prime number
BaseRepresentation
bin1011000001000100111011…
…0100101111000110011101
31120220000002212112211110222
42300101032310233012131
53041430142314100411
641432410055211125
72360100442022405
oct260211664570635
946800085484428
1012113130221981
113950171249028
121437732976aa5
1369b356566839
142dc3c87c5805
15160154c314db
hexb044ed2f19d

12113130221981 has 2 divisors, whose sum is σ = 12113130221982. Its totient is φ = 12113130221980.

The previous prime is 12113130221953. The next prime is 12113130222031. The reversal of 12113130221981 is 18912203131121.

12113130221981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8878045956025 + 3235084265956 = 2979605^2 + 1798634^2 .

It is a cyclic number.

It is not a de Polignac number, because 12113130221981 - 222 = 12113126027677 is a prime.

It is a super-2 number, since 2×121131302219812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12113130221281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056565110990 + 6056565110991.

It is an arithmetic number, because the mean of its divisors is an integer number (6056565110991).

Almost surely, 212113130221981 is an apocalyptic number.

It is an amenable number.

12113130221981 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113130221981 is an equidigital number, since it uses as much as digits as its factorization.

12113130221981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 35.

The spelling of 12113130221981 in words is "twelve trillion, one hundred thirteen billion, one hundred thirty million, two hundred twenty-one thousand, nine hundred eighty-one".