Base | Representation |
---|---|
bin | 10110100100000000… |
… | …01100100010101000 |
3 | 1011021012010101100221 |
4 | 23102000030202220 |
5 | 144301434420240 |
6 | 5321551535424 |
7 | 606114340513 |
oct | 132200144250 |
9 | 34235111327 |
10 | 12113201320 |
11 | 515664a490 |
12 | 242082a574 |
13 | 11b074b05c |
14 | 82ca87d7a |
15 | 4ad681a4a |
hex | 2d200c8a8 |
12113201320 has 64 divisors (see below), whose sum is σ = 29769249600. Its totient is φ = 4399342080.
The previous prime is 12113201281. The next prime is 12113201329. The reversal of 12113201320 is 2310231121.
It is a junction number, because it is equal to n+sod(n) for n = 12113201294 and 12113201303.
It is not an unprimeable number, because it can be changed into a prime (12113201329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 347236 + ... + 380524.
It is an arithmetic number, because the mean of its divisors is an integer number (465144525).
Almost surely, 212113201320 is an apocalyptic number.
12113201320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12113201320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14884624800).
12113201320 is an abundant number, since it is smaller than the sum of its proper divisors (17656048280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12113201320 is a wasteful number, since it uses less digits than its factorization.
12113201320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34138 (or 34134 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 12113201320 its reverse (2310231121), we get a palindrome (14423432441).
The spelling of 12113201320 in words is "twelve billion, one hundred thirteen million, two hundred one thousand, three hundred twenty".
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