Base | Representation |
---|---|
bin | 10001101000001000010… |
… | …100010110101111011111 |
3 | 11021210121222220112001112 |
4 | 101220020110112233133 |
5 | 124321241001044411 |
6 | 2324250050332235 |
7 | 153341434634123 |
oct | 21501024265737 |
9 | 4253558815045 |
10 | 1211320331231 |
11 | 42779982553a |
12 | 17691888a07b |
13 | 8a2c49ab25a |
14 | 428b1b81583 |
15 | 21798952b8b |
hex | 11a08516bdf |
1211320331231 has 2 divisors, whose sum is σ = 1211320331232. Its totient is φ = 1211320331230.
The previous prime is 1211320331203. The next prime is 1211320331239. The reversal of 1211320331231 is 1321330231121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211320331231 - 214 = 1211320314847 is a prime.
It is a super-2 number, since 2×12113203312312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1211320331197 and 1211320331206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211320331239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605660165615 + 605660165616.
It is an arithmetic number, because the mean of its divisors is an integer number (605660165616).
Almost surely, 21211320331231 is an apocalyptic number.
1211320331231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211320331231 is an equidigital number, since it uses as much as digits as its factorization.
1211320331231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1211320331231 its reverse (1321330231121), we get a palindrome (2532650562352).
The spelling of 1211320331231 in words is "one trillion, two hundred eleven billion, three hundred twenty million, three hundred thirty-one thousand, two hundred thirty-one".
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