Base | Representation |
---|---|
bin | 11011100010101101000011… |
… | …110111101001101001111100 |
3 | 120212220010010102010100222100 |
4 | 123202231003313221221330 |
5 | 111334112020413423400 |
6 | 1105343152532545100 |
7 | 34341335251435035 |
oct | 3342550367515174 |
9 | 525803112110870 |
10 | 121132101311100 |
11 | 35661921312380 |
12 | 11704267782190 |
13 | 5278928a26889 |
14 | 21cab79a8da8c |
15 | e00dcd456100 |
hex | 6e2b43de9a7c |
121132101311100 has 432 divisors, whose sum is σ = 430180881661440. Its totient is φ = 28253428454400.
The previous prime is 121132101311093. The next prime is 121132101311131. The reversal of 121132101311100 is 1113101231121.
121132101311100 is a `hidden beast` number, since 1 + 21 + 1 + 321 + 0 + 1 + 311 + 10 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 25246504 + ... + 29658896.
It is an arithmetic number, because the mean of its divisors is an integer number (995789077920).
Almost surely, 2121132101311100 is an apocalyptic number.
121132101311100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 121132101311100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215090440830720).
121132101311100 is an abundant number, since it is smaller than the sum of its proper divisors (309048780350340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121132101311100 is a wasteful number, since it uses less digits than its factorization.
121132101311100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4412530 (or 4412520 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 18.
Adding to 121132101311100 its reverse (1113101231121), we get a palindrome (122245202542221).
The spelling of 121132101311100 in words is "one hundred twenty-one trillion, one hundred thirty-two billion, one hundred one million, three hundred eleven thousand, one hundred".
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