Base | Representation |
---|---|
bin | 1011000001000101010001… |
… | …0111110011001110101011 |
3 | 1120220000100100200200112102 |
4 | 2300101110113303032223 |
5 | 3041430340131100021 |
6 | 41432423222204015 |
7 | 2360102652125051 |
oct | 260212427631653 |
9 | 46800310620472 |
10 | 12113223300011 |
11 | 3950209841a19 |
12 | 1437759b8360b |
13 | 69b36c9257b2 |
14 | 2dc3d6cd41d1 |
15 | 16015ceba00b |
hex | b04545f33ab |
12113223300011 has 2 divisors, whose sum is σ = 12113223300012. Its totient is φ = 12113223300010.
The previous prime is 12113223299953. The next prime is 12113223300023. The reversal of 12113223300011 is 11000332231121.
It is a happy number.
12113223300011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12113223300011 - 234 = 12096043430827 is a prime.
It is not a weakly prime, because it can be changed into another prime (12113223300091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056611650005 + 6056611650006.
It is an arithmetic number, because the mean of its divisors is an integer number (6056611650006).
Almost surely, 212113223300011 is an apocalyptic number.
12113223300011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113223300011 is an equidigital number, since it uses as much as digits as its factorization.
12113223300011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 12113223300011 its reverse (11000332231121), we get a palindrome (23113555531132).
The spelling of 12113223300011 in words is "twelve trillion, one hundred thirteen billion, two hundred twenty-three million, three hundred thousand, eleven".
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