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1211323813153 is a prime number
BaseRepresentation
bin10001101000001000100…
…001101000110100100001
311021210122020110102100121
4101220020201220310201
5124321242344010103
62324250253120241
7153341506345366
oct21501041506441
94253566412317
101211323813153
114277a0793563
12176919a89081
138a2c562a06c
14428b240a46d
1521798dde6bd
hex11a08868d21

1211323813153 has 2 divisors, whose sum is σ = 1211323813154. Its totient is φ = 1211323813152.

The previous prime is 1211323813123. The next prime is 1211323813159. The reversal of 1211323813153 is 3513183231121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1094381700129 + 116942113024 = 1046127^2 + 341968^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211323813153 - 25 = 1211323813121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1211323813159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605661906576 + 605661906577.

It is an arithmetic number, because the mean of its divisors is an integer number (605661906577).

Almost surely, 21211323813153 is an apocalyptic number.

It is an amenable number.

1211323813153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211323813153 is an equidigital number, since it uses as much as digits as its factorization.

1211323813153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960, while the sum is 34.

The spelling of 1211323813153 in words is "one trillion, two hundred eleven billion, three hundred twenty-three million, eight hundred thirteen thousand, one hundred fifty-three".