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12113314243193 is a prime number
BaseRepresentation
bin1011000001000101100111…
…0010101110001001111001
31120220000120200211002010102
42300101121302232021321
53041431031421240233
641432440231325145
72360105135126402
oct260213162561171
946800520732112
1012113314243193
113950256107979
1214377845207b5
1369b385717b27
142dc4050089a9
15160165e811e8
hexb0459cae279

12113314243193 has 2 divisors, whose sum is σ = 12113314243194. Its totient is φ = 12113314243192.

The previous prime is 12113314243181. The next prime is 12113314243307. The reversal of 12113314243193 is 39134241331121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10582321290304 + 1530992952889 = 3253048^2 + 1237333^2 .

It is a cyclic number.

It is not a de Polignac number, because 12113314243193 - 28 = 12113314242937 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12113314242193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056657121596 + 6056657121597.

It is an arithmetic number, because the mean of its divisors is an integer number (6056657121597).

Almost surely, 212113314243193 is an apocalyptic number.

It is an amenable number.

12113314243193 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113314243193 is an equidigital number, since it uses as much as digits as its factorization.

12113314243193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656, while the sum is 38.

The spelling of 12113314243193 in words is "twelve trillion, one hundred thirteen billion, three hundred fourteen million, two hundred forty-three thousand, one hundred ninety-three".