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12113333301300 = 22352721174912389
BaseRepresentation
bin1011000001000101101011…
…1011011011000000110100
31120220000122000200022221020
42300101122323123000310
53041431101311120200
641432442152021140
72360105456123400
oct260213273330064
946800560608836
1012113333301300
113950265944580
12143778a9917b0
1369b38965b60a
142dc40776a100
15160167997ea0
hexb045aedb034

12113333301300 has 216 divisors, whose sum is σ = 44476384891680. Its totient is φ = 2517056236800.

The previous prime is 12113333301271. The next prime is 12113333301317. The reversal of 12113333301300 is 310333331121.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 37294495 + ... + 37617894.

Almost surely, 212113333301300 is an apocalyptic number.

12113333301300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12113333301300 is an abundant number, since it is smaller than the sum of its proper divisors (32363051590380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12113333301300 is a wasteful number, since it uses less digits than its factorization.

12113333301300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74912431 (or 74912417 counting only the distinct ones).

The product of its (nonzero) digits is 1458, while the sum is 24.

Adding to 12113333301300 its reverse (310333331121), we get a palindrome (12423666632421).

It can be divided in two parts, 121133 and 33301300, that added together give a palindrome (33422433).

The spelling of 12113333301300 in words is "twelve trillion, one hundred thirteen billion, three hundred thirty-three million, three hundred one thousand, three hundred".