Base | Representation |
---|---|
bin | 10110100100000010… |
… | …00101011000010010 |
3 | 1011021012120012201112 |
4 | 23102001011120102 |
5 | 144302014343010 |
6 | 5322000533322 |
7 | 606116330330 |
oct | 132201053022 |
9 | 34235505645 |
10 | 12113434130 |
11 | 5156799396 |
12 | 2420921242 |
13 | 11b0800005 |
14 | 82cb08b50 |
15 | 4ad6caa05 |
hex | 2d2045612 |
12113434130 has 16 divisors (see below), whose sum is σ = 24919064640. Its totient is φ = 4153177392.
The previous prime is 12113434129. The next prime is 12113434141. The reversal of 12113434130 is 3143431121.
It is a junction number, because it is equal to n+sod(n) for n = 12113434096 and 12113434105.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86524460 + ... + 86524599.
It is an arithmetic number, because the mean of its divisors is an integer number (1557441540).
Almost surely, 212113434130 is an apocalyptic number.
12113434130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12113434130 is an abundant number, since it is smaller than the sum of its proper divisors (12805630510).
12113434130 is a wasteful number, since it uses less digits than its factorization.
12113434130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173049073.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 12113434130 its reverse (3143431121), we get a palindrome (15256865251).
The spelling of 12113434130 in words is "twelve billion, one hundred thirteen million, four hundred thirty-four thousand, one hundred thirty".
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