Base | Representation |
---|---|
bin | 1011000001000110000101… |
… | …0111100011001110000111 |
3 | 1120220000220112222011202122 |
4 | 2300101201113203032013 |
5 | 3041431311440310442 |
6 | 41432501011400155 |
7 | 2360111240331044 |
oct | 260214127431607 |
9 | 46800815864678 |
10 | 12113441338247 |
11 | 3950310925307 |
12 | 14377babb305b |
13 | 69b3a5b572c2 |
14 | 2dc417c501cb |
15 | 1601721d8dd2 |
hex | b04615e3387 |
12113441338247 has 2 divisors, whose sum is σ = 12113441338248. Its totient is φ = 12113441338246.
The previous prime is 12113441338241. The next prime is 12113441338303. The reversal of 12113441338247 is 74283314431121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12113441338247 - 26 = 12113441338183 is a prime.
It is a super-2 number, since 2×121134413382472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12113441338198 and 12113441338207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12113441338241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056720669123 + 6056720669124.
It is an arithmetic number, because the mean of its divisors is an integer number (6056720669124).
Almost surely, 212113441338247 is an apocalyptic number.
12113441338247 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113441338247 is an equidigital number, since it uses as much as digits as its factorization.
12113441338247 is an evil number, because the sum of its binary digits is even.
The product of its digits is 387072, while the sum is 44.
Adding to 12113441338247 its reverse (74283314431121), we get a palindrome (86396755769368).
The spelling of 12113441338247 in words is "twelve trillion, one hundred thirteen billion, four hundred forty-one million, three hundred thirty-eight thousand, two hundred forty-seven".
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