12113441342437 has 2 divisors, whose sum is σ = 12113441342438. Its totient is φ = 12113441342436.

The previous prime is 12113441342329. The next prime is 12113441342473. The reversal of 12113441342437 is 73424314431121.

Together with next prime (12113441342473) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9018765771876 + 3094675570561 = 3003126^2 + 1759169^2 .

It is an emirp because it is prime and its reverse (73424314431121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12113441342437 is a prime.

It is a super-2 number, since 2×12113441342437² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12113441342437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12113441342837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056720671218 + 6056720671219.

It is an arithmetic number, because the mean of its divisors is an integer number (6056720671219).

Almost surely, 2^{12113441342437} is an apocalyptic number.

It is an amenable number.

12113441342437 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113441342437 is an equidigital number, since it uses as much as digits as its factorization.

12113441342437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 193536, while the sum is 40.

Adding to 12113441342437 its reverse (73424314431121), we get a palindrome (85537755773558).

The spelling of 12113441342437 in words is "twelve trillion, one hundred thirteen billion, four hundred forty-one million, three hundred forty-two thousand, four hundred thirty-seven".