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12114001014 = 232019000169
BaseRepresentation
bin10110100100000110…
…01111110001110110
31011021020122000100020
423102003033301312
5144302141013024
65322021030010
7606124211133
oct132203176166
934236560306
1012114001014
115157046295
122420b55306
1311b096b04b
1482cc1558a
154ad78d979
hex2d20cfc76

12114001014 has 8 divisors (see below), whose sum is σ = 24228002040. Its totient is φ = 4038000336.

The previous prime is 12114000989. The next prime is 12114001051. The reversal of 12114001014 is 41010041121.

It is a sphenic number, since it is the product of 3 distinct primes.

12114001014 is an admirable number.

It is a super-3 number, since 3×121140010143 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12114000984 and 12114001002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1009500079 + ... + 1009500090.

It is an arithmetic number, because the mean of its divisors is an integer number (3028500255).

Almost surely, 212114001014 is an apocalyptic number.

12114001014 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12114001014 is a wasteful number, since it uses less digits than its factorization.

12114001014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2019000174.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 12114001014 its reverse (41010041121), we get a palindrome (53124042135).

The spelling of 12114001014 in words is "twelve billion, one hundred fourteen million, one thousand, fourteen".

Divisors: 1 2 3 6 2019000169 4038000338 6057000507 12114001014